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Configuration = 52
cycles = (10 6 1 9 2)(8 5 3 7 4)

a = 1, b = 3, c = 7
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cycles = (10 4 5 2 8 3 1 9 6)(7)

a = 4, b = 8, c = 10
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cycles = (10 3 1 5 8)(9)(7 2 4)(6)

a = 2, b = 4, c = 7
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cycles = (10 6 1 3 8)(9)(7)(5)(4)(2)

a = 6, b = 8, c = 10
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cycles = (10)(9)(8)(7)(6 1 3)(5)(4)(2)